Let E and F are the event of the occurrence of Head and Tail, respectively.

Probability of Occurrence of Head P(E) = No. of heads/total number of trials

P(E) = 455/1000 = 0.455

Similarly,

P(F) = No. of tails/total number of trials

P(F) = 545/1000 = 0.545

P(not E) = 1 – P(E) = 1-0.38 = 0.62

There are 4 aces in a deck of card.

Hence, the probability of taking one ace out of 52 cards = 4/52 = 1/13

No. of boundaries = 6

No. of balls = 30

No. of balls without boundaries = 30 – 6 =24

Probability of no boundary = 24/30 = ⅘

Sample space, S = {1, 2, 3, 4, 5, 6}

Favourable outcomes = {1, 3}

Therefore, the probability of getting an odd number less than 4 = 2/6 = ⅓.

In a pack of 52 cards, there are a total of 4 king cards, out of which 2 are red and 2 are black.

Therefore, in a red suit, there are 2 king cards.

Hence, the probability of getting a king of red suits = 2/52 = 1/26.

S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}

Multiples of 4 from the sample space = {4, 8, 12}

Therefore, the probability of the selected number is a multiple of 5 is 3/15 = 1/5.

Total balls = 4 green + 2 red = 6 balls

No. of red balls = 2.

Hence, the probability of getting the red balls = 2/6 = 1/3

Empirical probability is also known as experimental probability.

If two coins are tossed, then the sample space, S = {HH, HT, TH, TT}

Favourable outcome (Getting exactly two tails) = {TT}

Therefore, the probability of getting exactly two heads = 1/4

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